Skip to main content

important question on Entity Relationship Model(ER Model

9) Define the concept of aggregation. Give one examples of where this concept is useful.
Answer: Aggregation is an abstraction through which relationships are treated
as higher-level entities. Thus the relationship between entities A and B is treated

as if it were an entity C. Some examples of this are:
  • Employees work for projects. An employee working for a particular project
    uses various machinery.
 


10) An E-R diagram can be viewed as a graph. What do the following mean in terms of the structure of an enterprise schema?
a. The graph is disconnected.
b. The graph is acyclic.

Answer : 
     a)  If a pair of entity sets are connected by a path in an E-R diagram, the entity sets are related, though perhaps indirectly. A disconnected graph implies that there are pairs of entity sets that are unrelated to each other. If we split the graph into connected components, we have, in effect, a separate database corresponding to each connected component.
    b) As indicated in the answer to the previous part, a path in the graph between a pair of entity sets indicates a (possibly indirect) relationship between the two entity sets. If there is a cycle in the graph then every pair of entity sets
on the cycle are related to each other in at least two distinct ways. If the E - R
diagram is acyclic then there is a unique path between every pair of entity
sets and, thus, a unique relationship between every pair of entity sets.


11) A weak entity set can always be made into a strong entity set by adding to its attributes the primary key attributes of its identifying entity set. Outline what sort of redundancy will result if we do so.
Answer:
The primary key of a weak entity set can be inferred from its relation-
ship with the strong entity set. If we add primary key attributes to the weak
entity set, they will be present in both the entity set and the relationship set and
they have to be the same. Hence there will be redundancy.


12) Explain the distinction between condition-defined and user-defined constraints. Which of these constraints can the system check automatically? Explain your answer.
Answer:
In a generalization– specialization hierarchy, it must be possible to decide which entities are members of which lower level entity sets. In a condition defined design constraint, membership in the lower level entity-sets is evaluated on the basis of whether or not an entity satisfies an explicit condition or predicate.User-defined lower-level entity sets are not constrained by a member-
ship condition; rather, entities are assigned to a given entity set by the database
user.

Condition-defined constraints alone can be automatically handled by the system. Whenever any tuple is inserted into the database, its membership in the
various lower level entity-sets can be automatically decided by evaluating the
respective membership predicates. Similarly when a tuple is updated, its membership in the various entity sets can be re-evaluated automatically.

13) Explain the distinction between total and partial constraints.
Answer:
In a total design constraint, each higher-level entity must belong to a
lower-level entity set. The same need not be true in a partial design constraint.
For instance, some employees may belong to no work-team.

Comments

Popular posts from this blog

important question on Entity Relationship Model(ER Model)

5)A university registrar’s office maintains data about the following entities: (a) courses, including number, title, credits, syllabus, and prerequisites; (b) course offerings, including course number, year, semester, section number, instructor(s), timings, and classroom; (c) students, including student-id, name, and program; and (d) instructors, including identification number, name, department, and title. Further, the enrollment of students in courses and grades awarded to students in each course they are enrolled for must be appropriately modeled. Construct an E-R diagram for the registrar’s office. Document all assumptions that you make about the mapping constraints. Answer:   In the answer given here, the main entity sets are student, course, course-offering, and instructor. The entity set course-offering is a weak entity set dependent on course. The assumptions made are : a class meets only at one particular place and time. This E - R diagram cannot model a class meet

how to Install Numpy, Pandas and matplotlib on ubuntu 18.04 and Linux Mint

Install Python, NumPy,Matplotlib for Python 3 on Ubuntu 18.04, Linux Mint, Debian Linux. This is a short article about installing Numpy, Pandas , Matplotlib, Python3 on the latest Ubuntu 18.04 LTS, Linux Mint, Debian Linux which comes with Python 3.6.5. Let’s start by making sure we have an updated system: 1 sudo apt update 2 sudo apt upgrade Now, let’s install NumPy, Pandas,Matplotlib : sudo apt-get install python-pip sudo pip install numpy sudo pip install pandas sudo pip install matplotlib Test numpy : Open up a Terminal in Your Linux Operating System by running the following: python3 At the Terminal, type the following: >>> import numpy as np >>> np.__version__ '1.13.3'   Test Pandas : Open up a Terminal in Your Linux Operating System by running the following: python3 At the Terminal, type the following: >>> import pandas as pd >>> pd.__version__ '0.22.0'   Test Matpl

Library Management System DataFlow Diagram

Library Management System DataFlow Diagram 1) Zero Level DFD 2) 1st level DFD and 2nd level DFD